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Contains Duplicate II

Check if array has duplicates within k indices.

InputOutputExplanation
Example 1Result 1Explanation here
Example 2Result 2Explanation here
  • Constraints go here
ApproachTimeSpaceBest For
Hash Set Sliding WindowHashMap Index TrackingTree SetTBD
★ Recommended

Detailed explanation of approach 1.

⏱ Time O(n) 💾 Space O(n)
function solution():
// Pseudocode here
contains-duplicate-ii_approach1.py
"""
LeetCode #219: Contains Duplicate II
Approach: {approach}
"""
from typing import List, Dict, Set
def solution({param}) -> {return_type}:
"""
{description}
Time Complexity: O(n)
Space Complexity: O(n)
"""
pass
if __name__ == "__main__":
# Test cases
print(solution({test_input}))
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Detailed explanation of approach 2.

⏱ Time O(n) 💾 Space O(n)
contains-duplicate-ii_approach2.py
"""
LeetCode #219: Contains Duplicate II
Approach: {approach}
"""
from typing import List, Dict, Set
def solution({param}) -> {return_type}:
"""
{description}
Time Complexity: O(n)
Space Complexity: O(n)
"""
pass
if __name__ == "__main__":
# Test cases
print(solution({test_input}))
✓ Simple

Detailed explanation of approach 3.

⏱ Time O(n) 💾 Space O(n)
contains-duplicate-ii_approach3.py
"""
LeetCode #219: Contains Duplicate II
Approach: {approach}
"""
from typing import List, Dict, Set
def solution({param}) -> {return_type}:
"""
{description}
Time Complexity: O(n)
Space Complexity: O(n)
"""
pass
if __name__ == "__main__":
# Test cases
print(solution({test_input}))